Question 17: Predict the output.

Question 17: Predict the output. (Considering int for 4 bytes)

class BaseClass
{
public:
    int m_BaseData;
};

class DeriveClass : public BaseClass
{
public:
    int m_DeriveData;
    void printValues()
    {
        std::cout<<"\nBase Data : "<<m_BaseData;

        std::cout<<"\tDerive Data : "<<m_DeriveData;
    }
};

void BaseClassLoop (BaseClass *List, int Count)
{
    int i;

    for (i = 0; i < Count; ++i)
        List[i].m_BaseData = i;

}

int main()
{
    DeriveClass objList[2];
    BaseClassLoop(objList,2);
    for(int i =0;i< 2;i++)
    {
        objList[i].printValues();
    }
}

Options:

(a) Base Data: 0                                Derive Data: Garbage Value

      Base Data: 1                                Derive Data: Garbage Value

(b) Base Data: Garbage Value        Derive Data: Garbage Value

      Base Data: Garbage Value        Derive Data: Garbage Value

(c) Base Data: 0                                 Derive Data: 1

      Base Data: Garbage Value        Derive Data: Garbage Value

(d) None of the above.

Show Solution

Solution: c

Explanation :When object array is passed as an argument, a pointer to array is passed.
On incrementing the pointer it will increment as per the size of Base class that is by one integer instead of two, due to which next time when for loop executed the next memory location value is modified.

Question 16: Predict the output.

Question 16: Predict the output. (Considering int for 4 bytes)

    void display(int data[])
    {
        std::cout<<"\nSize of array when passed as argument is : "<<sizeof(data);
    }

    int main()
    {
        int data[] = { 1, 2, 3, 4, 5, 6};

        std::cout<<"\nSize of array is : "<<sizeof(data);
        printSizeOfArray(data);
        
    }

    

    Options:
    (a) Size of array is : 24
         Size of array when passed as argument is : 4

    (b) Size of array is : 24
         Size of array when passed as argument is : 24

    (c) Compile Time error.

    (d) None of the above.

Show Solution

Solution: a

Explanation : The value will be passed as pointer instead of whole data.

In C and C++ it is NOT possible to pass a complete block of memory by value as a parameter to a function, but we are allowed to pass its address. In practice this has almost the same effect and it is a much faster and more efficient operation.

To be safe, you can pass the array size or put const qualifier before the pointer to make sure the callee won't change it.

Question 15: Predict the output.

class DemoClass
{
public:
    void display()
    {
        std::cout<<"\nDisplay Function 1";
    }
    void display() const
    {
        std::cout<<"\nDisplay Function 2";
    }
};


int main()
{
    DemoClass obj;
    obj.display();
}




Options:
(a) Display Function 1
(b) Runtime Error
(c) Compile Time error: error C2535: 'void DemoClass::display(void)' : member function already defined or declared.
(d) None of the above.




     Answer: a

Question 14: Predict the output.

class
{
public:
    void display()
    {
        std::cout<<"Display function without any class name";
    }
}classWithoutAnyName;


int main()
{
    classWithoutAnyName.display();
}






Options:
(a) Display function without any class name.
(b) Runtime Error
(c) Compile Time error: Class doesn’t have any name.
(d) None of the above.




Answer: a

Question 13: Predict the output.

class Base
{
public:
    void display()
    {
        std::cout<<"\nBase class display function.";
    }
};


class Derive : public Base
{
public:
    void display()
    {
        std::cout<<"\nDerive class display function.";
    }
};


int main()
{
    Base* obj = new Derive();
    obj->display();
}




Options:
(a) Base class display function.
(b) Derive class display function.
(c) Compile Time error: error C2248: 'Base:: display’ : cannot access private member declared in class 'Base'
(d) Runtime Error




Answer: a

Question 12: Predict the output.

int main()
{
    char str1[] = "India";
    char str2[] = "India";
    if(str1 == str2)
    {
        std::cout<<"Both the strings are same";
    }
    else
    {
        std::cout<<"Both the strings are not same";
    }
}






Options:
(a) Both the strings are same
(b) Both the strings are not same
(c) Compile Time error
(d) Runtime Error




Answer: b

Question 11:  Predict the output

int main()
{
    int x = 0;
    while(x++<5)
    {
        static int x;
        x += 2;
        std::cout<<x<<" ";
    }
}




Options:


a)     1 2 3 4 5
b)    2 4 6 8 10
c)     Compile Time error
d)    Runtime Error




Answer: b